Interactive Applet |
You can move the points A, B and C (click on the point and drag it).
Press the keys “+” and “−” to zoom in or zoom out the visualization window and use the arrow keys to translate it.
You can also construct all centers related with this one (as described in ETC) using the “Run Macro Tool”. To do this, click on the icon , select the center name from the list and, then, click on the vertices A, B and C successively.
Information from Kimberling's Encyclopedia of Triangle Centers |
Trilinears f(a,b,c) : f(b,c,a) : f(c,a,b), where f(a,b,c) = bc[(a - b + c)(a - c)2 + (a + b - c)(a - b)2]
Barycentrics af(a,b,c) : bf(b,c,a) : cf(c,a,b)
X(3035) lies on the Spieker circle and these lines:
1,1145 2,11 3,119 8,1317 9,1768 10,140 12,404 36,529 40,1537 80,1698 104,631 153,2551 230,1575 405,2932 468,1861 474,498 516,1638 549,993 620,2787 632,1484 676,2804 899,1818 908,1155 960,2800 1125,1387 1532,2077 2801,3041 2826,3039 2827,3038X(3035) = midpoint of X(I) and X(J) for these I,J: 1,1145 3,119 8,1317 10,214 11,100 40,1537 908,1155 1532,2077
X(3035) = reflection of X(I) in X(J) for these I,J: 1387,1125 3036,10
X(3035) = complement of X(11)
X(3035) = X(885)-Ceva conjugate of X(518)